Strong convergence for tensor GUE random matrices | Vidéo | Carmin.tv

00:00:00 / 00:00:00

Strong convergence for tensor GUE random matrices

De Wangjun Yuan

Apparaît dans la collection : Jean Morlet Chair - Research school: Random quantum channels: entanglement and entropies / Chaire Jean Morlet - Ecole: Canaux quantiques aléatoires: Intrication et entropies

Haagerup and Thorbjørnsen proved that iid GUEs converge strongly to free semicircular elements as the dimension grows to infinity. Motivated by considerations from quantum physics -- in particular, understanding nearest neighbor interactions in quantum spin systems -- we consider iid GUE acting on multipartite state spaces, with a mixing component on two sites and identity on the remaining sites. We show that under proper assumptions on the dimension of the sites, strong asymptotic freeness still holds. Our proof relies on an interpolation technology recently introduced by Bandeidra, Boedihardjo and van Handel. This is a joint work with Benoît Collins.

Informations sur la vidéo

Date de captation 08/07/2024
Date de publication 26/07/2024
Institut CIRM
Licence CC BY NC ND
Langue Anglais
Audience Chercheurs, Doctorants
Réalisateur(s) Guillaume Hennenfent
Format MP4

Données de citation

DOI 10.24350/CIRM.V.20200603
Citer cette vidéo Yuan, Wangjun (08/07/2024). Strong convergence for tensor GUE random matrices. CIRM. Audiovisual resource. DOI: 10.24350/CIRM.V.20200603
URL https://dx.doi.org/10.24350/CIRM.V.20200603

Domaine(s)

Bibliographie

BANDEIRA, Afonso S., BOEDIHARDJO, March T., et VAN HANDEL, Ramon. Matrix concentration inequalities and free probability. Inventiones mathematicae, 2023, vol. 234, no 1, p. 419-487. - https://doi.org/10.1007/s00222-023-01204-6
HAAGERUP, Uffe et THORBJØRNSEN, Steen. A new application of random matrices: $\text{Ext}(C_{\text{red}}^{\ast}(F_{2}))$ is not a group. Annals of Mathematics, 2005, p. 711-775. - https://www.jstor.org/stable/20159928

Codes MSC

Dernières questions liées sur MathOverflow

Pour poser une question, votre compte Carmin.tv doit être connecté à mathoverflow

Poser une question sur MathOverflow

Copyright Carmin.tv 2025

Donner son avis